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  strFileName = Request.QueryString("file1")
  Set objStream = Server.CreateObject("ADODB.Stream")
  objStream.Type = 1 ' adTypeBinary
  objStream.Open
  objStream.LoadFromFile strFileName
  objStream.SaveToFile Server."123_onweb.gif",2

  ʹÓ÷½·¨£º

  °ÑÉÏÃæµÄ´úÂëд³Éupload.asp
  ÔÚä¯ÀÀÆ÷ÀïÃæÊäÈ룺
  http://XXX/upload.asp?file1=c:/ÉÏ´«Îļþ/123.gif
  XXXΪÄãµÄÖ÷»úµØÖ·
  Ö´ÐÐÍêºóÄã»á¿´µ½ÄãµÄĿ¼ÏÂÃæ¶àÁËÒ»¸ö123_onweb.gif
  Ëû¾ÍÊÇÄãÒªÎļþÀ­£¡£¡£¡£¡

  ¸ù¾ÝÔ­ÀíÎÒÃÇ¿ÉÒÔÀ©Õ¹ÒÔÏ´úÂ룺
  upload.aspÎļþ
  <%
  Function GetFileName(ByVal strFile)
  If strFile <> "" Then
   GetFileName = mid(strFile,InStrRev(strFile, "/")+1)
  Else
   GetFileName = ""
  End If
  End  function

  strFileName = Request.Form("file1")
  Set objStream = Server.CreateObject("ADODB.Stream")
  objStream.Type = 1 ' adTypeBinary
  objStream.Open
  objStream.LoadFromFile strFileName
  objStream.SaveToFile Server.MapPath(GetFileName(strFileName)),2
  objStream.Close
  %>

  upload.htmÎļþ
  <form name="FORM" action="upload.asp" method="post">
¡¡¡¡<input type="submit" name="submit" value="OK">
     <input type="file" name="file1" style="width:400"  value="">
  </form>